0=8x^2+8x-16

Solution for 0=8x^2+8x-16 equation:

0=8x^2+8x-16

We move all terms to the left:

0-(8x^2+8x-16)=0

We add all the numbers together, and all the variables

-(8x^2+8x-16)=0

We get rid of parentheses

-8x^2-8x+16=0

a = -8; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·(-8)·16
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-24}{2*-8}=\frac{-16}{-16}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+24}{2*-8}=\frac{32}{-16}
=-2
$